Heat

* Heat type 

Formulas :

with the following provisions:

Q = Heat received a substance (Joule, kilojoules, calories, kilocalories)
M  = Mass of substance (Gram, Kilogram)
 C = Heat type (Joule / kilogram ° C, Joule / gram ° C, Calories / gram ° C)
  = Changes in temperature (° C) → (t2 - t1)

* To find the heat type, the formula is:

* To find the mass of substance, the formula is:

* Heat Capacity

Heat capacity is the amount of heat needed by the body to raise its temperature 1 ° C.

* The formula for heat capacity:

 rovided that:

Q = Heat received a substance (Joule, kilojoules, calories, kilocalories)
 H = Heat capacity (Joules / ° C)
 M = Mass of substance (Gram, Kilogram)
 C = Heat type (Joule / kilogram ° C, Joule / gram ° C, Calories / gram ° C)
  = Changes in temperature (° C) → (t2 - t1) 

*  Heat melting 

     Formulas:

    with the following provisions:

Q = Heat received a substance (Joule, kilojoules, calories, kilocalories)
M = Mass of substance (Gram, Kilogram)
L = Heat melting substances (Joule / kg, kilojoules / kilogram, joule / gram)

* Steam Heat  

   Formulas:

with the following provisions:
Q = Heat received a substance (Joule, kilojoules, calories, kilocalories)
M = Mass of substance (Gram, Kilogram)
U = Heat steam substances (Joule / kg, kilojoules / kilogram, joule / gram)

* Principle Black  Formulas:


 The principle of Black: The amount of heat received equal to the amount of heat released *Example Problem:

1.How much heat energy needed to vaporize 5 Kg of water at its boiling point, if the steam heat 2.26 million Joules / Kilogram? Answer: Given: m = 5 kg
             U = 2,260,000 J / Kg Asked: Q =..... ? Answer Q = m x U
        = 5 kg x 2.26 million J / Kg
        = 11,300,000 J         = 11.3 x 106 J